Advent of Code 2022 Day 19

— Day 19: Not Enough Minerals —

Determine the quality level of each blueprint using the largest number of geodes it could produce in 24 minutes. What do you get if you add up the quality level of all of the blueprints in your list?

import re

with open('data-2022-19.txt', 'r') as f:
    inp = f.read().splitlines()

Borrow this code from day 15 to get the information

# Blueprint 1
b = r'Blueprint (\d+).*'
blueprint = [int(re.match(b, i)[1]) for i in inp] 
blueprint 

# ore robot costs 3 ore
c = r'.*ore robot costs (\d+).*'
ore = [int(re.match(c, i)[1])  for i in inp]
ore 

# clay robot costs 3 ore
d = r'.*clay robot costs (\d+).*'
clay = [int(re.match(d, i)[1])  for i in inp]
clay

# obsidian robot costs 3 ore and 20 clay
e = r'.*obsidian robot costs (\d+) ore and (\d+).*'
obs = [[int(re.match(e, i)[1]), int(re.match(e, i)[2])]  for i in inp]
obs

# geode robot costs 2 ore and 12 obsidian
f = r'.*geode robot costs (\d+) ore and (\d+).*'
geo = [[int(re.match(f, i)[1]), int(re.match(f, i)[2])]  for i in inp]
geo 

robots = [[x[0], x[1], x[2], x[3], x[4]] 
               for x in zip(blueprint, ore, clay, obs, geo)]

Loop through these with the rules.

We start with one ore collecting robot. Assumption: we don’t want to build any more ore collecting robots, because obsidian robots rely on clay and geode robots rely on obsidian. A good check will be if we have enough clay but not enough ore or if we have enough obsidian but not enough ore. Luckily we have a hierarchy of robots (this is bound to be a difficulty in part two).

bank = {'oe': 0, 'cl': 0, 'ob': 0, 'ge': 0}

for r in robots: 
    for m in range(24): 
        pass