Advent of Code 2023 Day 6

— Day 6: Wait For It —

Determine the number of ways you could beat the record in each race.

What do you get if you multiply these numbers together?

with open('data-2023-06.txt', 'r') as f:
    inp = f.read().splitlines()

Time = inp[0].split()[1:]
Distance = inp[1].split()[1:]

Time = [int(x) for x in Time]
Distance = [int(x) for x in Distance]

This seems straightforward - solved on google sheets to start with.

# this is our answer, multiplied together
mult = 1

for d,t in zip(Distance, Time):
    # count of choices that make it past the distance
    cnt = 0
    # pretty sure it's not going to matter that we don't use the last one
    for x in range(t):
        z = (t - x) * x
        if z > d:
            cnt += 1
    # once we've gone through, multiply
    mult *= cnt
    
mult

2374848

Part one: 2374848

— Part Two —

Actually there was only one race

How many ways can you beat the record in this one much longer race?

Time = int(''.join(inp[0].split()[1:]))
Distance = int(''.join(inp[1].split()[1:]))

# count of choices that make it past the distance
cnt = 0

# pretty sure it's not going to matter that we don't use the last one
for x in range(0, Time, 1):
    z = (Time - x) * x
    if z > Distance:
        cnt += 1
        
cnt

39132886

Part two: 39132886